finitestrain.pyΒΆ
In this script we solve the nonlinear Saint Venant-Kichhoff problem on a unit square domain (optionally with a circular cutout), clamped at both the left and right boundary in such a way that an arc is formed over a specified angle. The configuration is constructed such that a symmetric solution is expected.
9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 | from nutils import mesh, function, solver, export, cli, testing
import numpy
def main(nelems:int, etype:str, btype:str, degree:int, poisson:float, angle:float, restol:float, trim:bool):
'''
Deformed hyperelastic plate.
.. arguments::
nelems [10]
Number of elements along edge.
etype [square]
Type of elements (square/triangle/mixed).
btype [std]
Type of basis function (std/spline).
degree [1]
Polynomial degree.
poisson [.25]
Poisson's ratio, nonnegative and stricly smaller than 1/2.
angle [20]
Rotation angle for right clamp (degrees).
restol [1e-10]
Newton tolerance.
trim [no]
Create circular-shaped hole.
'''
domain, geom = mesh.unitsquare(nelems, etype)
if trim:
domain = domain.trim(function.norm2(geom-.5)-.2, maxrefine=2)
bezier = domain.sample('bezier', 5)
ns = function.Namespace()
ns.x = geom
ns.angle = angle * numpy.pi / 180
ns.lmbda = 2 * poisson
ns.mu = 1 - 2 * poisson
ns.ubasis = domain.basis(btype, degree=degree).vector(2)
ns.u_i = 'ubasis_ki ?lhs_k'
ns.X_i = 'x_i + u_i'
ns.strain_ij = '.5 (u_i,j + u_j,i)'
ns.energy = 'lmbda strain_ii strain_jj + 2 mu strain_ij strain_ij'
sqr = domain.boundary['left'].integral('u_k u_k d:x' @ ns, degree=degree*2)
sqr += domain.boundary['right'].integral('((u_0 - x_1 sin(2 angle) - cos(angle) + 1)^2 + (u_1 - x_1 (cos(2 angle) - 1) + sin(angle))^2) d:x' @ ns, degree=degree*2)
cons = solver.optimize('lhs', sqr, droptol=1e-15)
energy = domain.integral('energy d:x' @ ns, degree=degree*2)
lhs0 = solver.optimize('lhs', energy, constrain=cons)
X, energy = bezier.eval(['X_i', 'energy'] @ ns, lhs=lhs0)
export.triplot('linear.png', X, energy, tri=bezier.tri, hull=bezier.hull)
ns.strain_ij = '.5 (u_i,j + u_j,i + u_k,i u_k,j)'
ns.energy = 'lmbda strain_ii strain_jj + 2 mu strain_ij strain_ij'
energy = domain.integral('energy d:x' @ ns, degree=degree*2)
lhs1 = solver.minimize('lhs', energy, lhs0=lhs0, constrain=cons).solve(restol)
X, energy = bezier.eval(['X_i', 'energy'] @ ns, lhs=lhs1)
export.triplot('nonlinear.png', X, energy, tri=bezier.tri, hull=bezier.hull)
return lhs0, lhs1
|
If the script is executed (as opposed to imported), nutils.cli.run()
calls the main function with arguments provided from the command line. For
example, to keep with the default arguments simply run python3
finitestrain.py
(view log). To select quadratic splines and a cutout add python3
finitestrain.py btype=spline degree=2 trim=yes
(view log).
77 78 | if __name__ == '__main__':
cli.run(main)
|
Once a simulation is developed and tested, it is good practice to save a few
strategic return values for regression testing. The nutils.testing
module, which builds on the standard unittest
framework, facilitates
this by providing nutils.testing.TestCase.assertAlmostEqual64()
for the
embedding of desired results as compressed base64 data.
86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 | class test(testing.TestCase):
@testing.requires('matplotlib')
def test_default(self):
lhs0, lhs1 = main(nelems=4, etype='square', btype='std', degree=1, poisson=.25, angle=10, restol=1e-10, trim=False)
with self.subTest('linear'): self.assertAlmostEqual64(lhs0, '''
eNpjYMAE5ZeSL/HqJ146YeB4cbvhl/PzjPrOcVy8da7b4Og5W6Osc/rGt88+MvY+u+yC7NlcQ+GzEsYP
z/w3nn1mvon7mdsXJM8oG304vdH45Oluk2WnlU1bTgMAv04qwA==''')
with self.subTest('non-linear'): self.assertAlmostEqual64(lhs1, '''
eNpjYMAEZdrKl2/p37soY1h84aKh2/lmI4Zz7loq5y0MD55rNtI652Rcefa48aUzzZcjzj4ylDjrYnz6
jIBJ8Zl2E9Yzty9InlE2+nB6o/HJ090my04rm7acBgAKcSdV''')
@testing.requires('matplotlib')
def test_mixed(self):
lhs0, lhs1 = main(nelems=4, etype='mixed', btype='std', degree=1, poisson=.25, angle=10, restol=1e-10, trim=False)
with self.subTest('linear'): self.assertAlmostEqual64(lhs0, '''
eNpjYICAqxfbL+Xov7kIYi80OA+mtxleOA+iVxjNPBdncOdc6sXT51yNgs8ZGX89e8/Y66zqBaOz/Ya8
Z4WMX575ZTz5zAqTgDPKRh9O374geWaj8cnT3SbLTiubtpwGAJ6hLHk=''')
with self.subTest('non-linear'): self.assertAlmostEqual64(lhs1, '''
eNpjYIAA7fv2l6UMEi6C2H8N7l0A0VcMzc+D6H4jznPyhpfOdelwnm80EjznYTz57CnjG2eWX0o/+9VQ
+KyT8cUzzCbZZ2abiJ9RNvpw+vYFyTMbjU+e7jZZdlrZtOU0AJN4KHY=''')
@testing.requires('matplotlib')
def test_spline(self):
lhs0, lhs1 = main(nelems=4, etype='square', btype='spline', degree=2, poisson=.25, angle=10, restol=1e-10, trim=False)
with self.subTest('linear'): self.assertAlmostEqual64(lhs0, '''
eNpjYMAOrl3J0vmixaY7QS9N545+w9VaA5eLXYZp51MvVl/I1F164YeBxAVlI//zzMZB52KN35+dd+H9
2Vd6b85yGx0/a22cd/aXMetZH5PTZ7ZfaDmzTL/nzFGj3DPPje3OLDBhPvPC5N7p2xckz/gZsJwRML5z
Wstk++m7JlNPK5u2nAYATqg9sA==''')
with self.subTest('non-linear'): self.assertAlmostEqual64(lhs1, '''
eNpjYMAOnLUP6ejq9ukI67vflTVQvdRt0H8h3fDBOT7trReK9adeyDFcez7YaN+5X0Z7z7oYB5/9rKx9
ztdA6Fyq0dqzScbGZ78bLzmja5J8RvzSrjN9BgvOfDFKP/PTWOfMSpO3p8+YbDx9+4LkGT8DljMCxndO
a5lsP33XZOppZdOW0wApLzra''')
|